Question

The circumference of the base of a cylindrical vessel is $132$cm and its height is $25$cm. How many liters of water can it hold

Answer 1

Given $C=132$cm, $h=25$cm

Let the radius of the base $=$r

$2\pi r=132$cm

$\therefore 2\times \frac{22}{7}\times r=132$cm

$\therefore r=\frac{132}{2\times \frac{22}{7}}=\frac{132\times 7}{2\times 22}=21$

$\therefore r=21$cm

Volume of the vessel$=\pi r^{2}h=\frac{22}{7}\times (21{)}^2\times 25c{m}^3=\frac{22}{7}\times 21\times 21\times 25c{m}^3=34650c{m}^3$.

Volume in litres $=\frac{34650}{1000}[\because 1000c{m}^3=1l]=34.65$litres

$\therefore$ The vessel can hold $34.65$ liters of water.