Question

The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm. How many liters of water can it hold? (1000 cm³ = 1 $l$)

Answer 1

Let the radius of the base of the cylindrical vessel be r cm.
∴2πr = 132 cm [circumference = 2πr]
⇒ 2×$\frac{22}{7}\times r=132\Rightarrow r=\frac{132\times 7}{2\times 22}cm=21cm$
Now, radius (r) = 21 cm and height (h) = 25 cm
⇒ Volume of the cylindrical vessel
= πr²h =$\frac{22}{7}\times$ 21 × 21× 25 cm³ = 34650 cm³
∴ Vol. of water which this vessel can hold
= Volume of the vessel = 34650 cm³ = $\frac{34650}{1000}l$
[1000 cm³ = 1 $l$]
= 34.65 $l$