the circumference of the front wheel of a car is 10 dm and that of the hind wheel in 16 dm. how many reveloutions more will the first wheel make than the second in covering a distance of 96 km?

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Solution

We know that,
1 km = 10000 dm

Now, 96 km = 960000 dm

FOR FRONT WHEEL :

Circumference of front wheel = 10 dm
Number of revolutions taken to cover 10 dm = 1
So, number of revolutions taken to cover 960000 dm = 960000/10 = 96000

FOR HIND WHEEL :

Circumference of hind wheel = 16 dm
Number of revolutions taken to cover 16 dm = 1
So, number of revolutions taken to cover 960000 dm = 960000/16 = 6000

Number of extra revolutions made by hind wheel than front wheel = 96000 - 6000 = 36000

96000−60000=36000 96000−60000=36000

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