Question

The circumference of the front wheel of a cart is $3m$ long and that of the back wheel is $4m$ long. What is the distance traveled by the cart, when the front wheel makes five more revolutions than the rear wheel?

Answer 1

Given, the circumference of front-wheel $=3m$

and, the circumference of back wheel $=4m$

Let the distance travelled by the cart be ${}^{\prime }{x}^{\prime }$ metres

Number of revolutions $=\frac{\text{Distance Travelled}}{\text{Circumference}}$

Number of revolutions of front wheel $=\frac{x}{3}$

Number of revolutions of back wheel $=\frac{x}{4}$

It is given that the front wheel makes five more revolutions than the rear wheel.

$\therefore$ $\frac{x}{3}-\frac{x}{4}=5$

$\Rightarrow \frac{4x-3x}{12}=5$

$\Rightarrow x=60$

Hence, the distance covered by the cart is $60m.$