Question

The circumradius of a triangle with its vertices at (1, -2), (-3, 0) and (5, 6) is

• A. 5
• B. 10
• C.
• D.

Answer 1

The correct option is A 5

A(1, - 2) ,B(- 3, 0) and C(5, 6)

AB = $\sqrt{20}$, BC = $\sqrt{100}$ , AC = $\sqrt{80}$

$B{C}^2=A{B}^2+A{C}^2$

ABC is a right angled triangle with the right angle at A.

Circumradius is half the length of the hypotenuse.

R = $\frac{1}{2}\times$ BC, BC = 5. Option(a).