Question

The $Cl-C-Cl$ angle in $1,1,2,2-$tetrachloroethene and tetrachloromethane respectively will be about

• A. ${120}^{\circ }$ and ${109.5}^{\circ }$
• B. ${90}^{\circ }$ and ${109.5}^{\circ }$
• C. ${109.5}^{\circ }$ and ${90}^{\circ }$
• D. ${109.5}^{\circ }$ and ${120}^{\circ }$

Answer 1

The correct option is A ${120}^{\circ }$ and ${109.5}^{\circ }$

The bond angle in $s{p}^3,s{p}^2$ and $sp$ hybridisation is respectively ${109.5}^{\circ }$,${120}^{\circ }$ and ${180}^{\circ }$.
Tetrachloroethene being an alkene has $s{p}^2$ hybridised $C-atoms$ and hence the $Cl-C-Cl$ angle is ${120}^{\circ }$, whereas in tetrachloromethane, carbon is $s{p}^3$ hybridised, so the angle is ${109.5}^{\circ }$.