The class marks of a distribution are $105, 115, 125, 135, 145, 155, 165$ . The class size is:

5

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10

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15

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20

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Solution

The correct option is B $10$
Since, class size $=$ Difference between any two consecutive class marks
$= 115 - 105$
$= 10$
Option $B$ is correct.

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The class marks of a distribution are 105,115,125,135,145,155,165. The class size is:

The correct option is B 10Since, class size = Difference between any two consecutive class marks =115−105 =10Option B is correct.

The class marks of a distribution are $105, 115, 125, 135, 145, 155, 165$ . The class size is:

The correct option is B $10$
Since, class size $=$ Difference between any two consecutive class marks
$= 115 - 105$
$= 10$
Option $B$ is correct.