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Question

The close loop transfer function of a system is,T(s)=s3+4s2+8s+16s5+3s4+5s2+4s+3
The number of poles in the right half plane and in left half plane are

A
3, 2
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B
1, 4
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C
2, 3
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D
4, 1
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Solution

The correct option is C 2, 3
Characteristic equation is s5+3s4+5s2+4s+3=0

The Routh table for the characteristic equation corresponding to the given transfer function is:

There are two sign changes in the first column of Routh table. So there are 2 poles in RHP. Order of the characteristic equation is 5 = number of poles

No.of poles in LHP = 5 - 2 = 3

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