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Question

The closed loop frequency response |G(jω)| versus frequency of a second order prototype system is shown in figure below.


The corresponding unit step response of the system is

A
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B
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C
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D
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Solution

The correct option is C
At resonant frequency, resonant peak is achieved.

Mr=1.6,

ωr=4

Mrandωr are given by

Mr=12ξ1ξ2

ωr=ωn12ξ2

Now, 1.6=12ξ1ξ2

4ξ44ξ2+(1016)2=0

ξ=0.94,0.33(ωr to exist 12ξ2>0;ξshouldbelessthan12)

ξ=0.33

and ωn=412(0.33)2

ωn=4.53rad/sec

Setting time for 2% tolerance band is,

ts=4ξωn=40.33×4.53=2.7sec


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