The closed loop frequency response |G(jω)| versus frequency of a second order prototype system is shown in figure below.
The corresponding unit step response of the system is
Mrandωr are given by
Mr=12ξ√1−ξ2
ωr=ωn√1−2ξ2
Now, 1.6=12ξ√1−ξ2
4ξ4−4ξ2+(1016)2=0
ξ=0.94,0.33(ωr to exist 1−2ξ2>0;ξshouldbelessthan1√2)
ξ=0.33
and ωn=4√1−2(0.33)2
ωn=4.53rad/sec
Setting time for 2% tolerance band is,
ts=4ξωn=40.33×4.53=2.7sec