The closed loop line integral ∮|z|=5z3+z2+8z+2dz
evaluated counterclockwise, is
A
−4jπ
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B
+8jπ
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C
−8jπ
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D
+4jπ
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Solution
The correct option is B+8jπ According to Cauchy's integral formula f(a)=12πj∫cf(z)(z−a)dz
(if f(z) is analytic within an on the closed curve C)
Hence, ∫cf(z)(z−a) {where, f(z)=z3+z2+8} =2πjf(−2) {∵a=−2} =2πj(−8+4+8) =+j8π