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Question

The co-ordinate of the point on the circle x2+y212x4y+30=0, which is farthest from the origin are:

A
(9, 3)
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B
(8, 5)
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C
(12, 4)
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D
none
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Solution

The correct option is A (9, 3)
C = (6, 2) P = (0, 0) CP=40=210 r=10
Farthest point B divides ¯¯¯¯¯¯¯¯CP is in the ratio r : CP + r enternally
r : CP + r = 1 : 3
B=3(6,2)1(0,0)2=(9,3)

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