The co-ordinates of A, B, C are (6, 3), (-3, 5), (4, - 2) respectively and P is a point (x,y), then find the value of ΔPBCΔABC:
A
x+y−27
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B
x−y4
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C
x+y−35
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D
none of these
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Solution
The correct option is Ax+y−27 Area of ΔPBC=12{(5x+3y)+(6−20)+(4y+2x)}=12(7x+7y−14)=72(x+y−2) and area of ΔABC=12{(30+9)+(6−20)+(12+12)}=492 Hence ΔPBCΔABC=x+y−27