The co-ordinates of head and tail of a vector are (2,1,0) and (−4,2,−3) respectively . The magnitude of the vector is:
A
√23 units
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B
√46 units
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C
√84 units
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D
√12 units
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Solution
The correct option is B√46 units Position Vector of head =2ˆi+ˆj Position Vector of tail =−4ˆi+2ˆj−3ˆk Vector =(−4ˆi+2ˆj−3ˆk)−(2ˆi+ˆj) = −6ˆi+ˆj−3ˆk ∴ Magnitude of vector =√(−6)2+12+(−3)2=√46