Question

The co – ordinates of the extremities of the latus rectum of the parabola $5y^2=4x$ are

• A. $(\frac{1}{5},\frac{2}{5}),(\frac{-1}{5},\frac{2}{5})$
• B. $(\frac{1}{5},\frac{2}{5}),(\frac{1}{5},\frac{-2}{5})$
• C. $(\frac{1}{5},\frac{4}{5}),(\frac{1}{5},\frac{-4}{5})$
• D. $Noneofthese$

Answer 1

The correct option is B $(\frac{1}{5},\frac{2}{5}),(\frac{1}{5},\frac{-2}{5})$

The given parabola is of the form $y^2=4ax$
End points of latus rectum of this parabola are (a,2a) and (a, -2a).
$y^2=4.\frac{1}{5}x;a=\frac{1}{5}$
=> End points of latus are $(\frac{1}{5},\pm \frac{2}{5})$