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Question

The co-ordinates of the foot of the perpendicular from (a,0) on the line y=mx+am are :

A
(0,1a)
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B
(0,am)
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C
(0,am)
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D
(0,1a)
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Solution

The correct option is D (0,am)
Let (h,k) be the required point.

hpa=kqb=(a×p+b×q+c)a2+b2

ham2=k0m=(m2a+a)m4+m2
ham2=km=am2
h=0,k=am
Hence, the required point is
(0,am)

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