The correct option is B (2,−1)
Let (h,k) be the point of reflection.
Line joining (0,0) and (h,k) is perpendicular to 4x−2y−5=0
Product of slopes of these lines is −1
kh∗2=−1=>k=−h2
Midpoint of (0,0) and (h,k) i.e, (h2,k2) lies on 4x−2y−5=0
Therefore 4h2−2k2−5=0=>2h−k−5=0 but k=−h2
2h+h2−5=0=>h=2 and k=−1
Point of reflection is (2,−1).