The co-ordinates of the point on x-axis which is equidistant from the points A(5, 4) and B(– 2, 3) is:
(2,0)
Any point on x axis is of the form C(x, 0)
Given that AC = BC
⇒AC2 = BC2
⇒(x−5)2 + 42 = (x+2)2+ 32
⇒x2 + 25 - 10x + 16 = x2 + 4 + 4x + 9
⇒14x=28
⇒x=2