The co-ordinates of two points P and Q are (2, 6) and (-3, 5) respectively. Find :
(i) the gradient of PQ;
(ii) the equation of PQ;
(iii) the co-ordinates of the point where PQ intersects the x-axis.
Given, co-ordinates of two points P and Q are (2, 6) and (-3, 5) respectively.
(i) Gradient of PQ =
(ii) The equation of the line PQ is given by:
y - y1 = m(x - x1)
y - 6 = (x - 2)
5y - 30 = x - 2
5y = x + 28
(iii) Let the line PQ intersects the x-axis at point A (x, 0).
Putting y = 0 in the equation of the line PQ, we get,
0 = x + 28
x = -28
Thus, the co-ordinates of the point where PQ intersects the x-axis are A (-28, 0).