Question

The coach of a cricket team buys $3$ bats and $6$ balls for $Rs.3900$. Later, she buys another bat and $3$ more balls of the same kind for $Rs.1300$. Represent this situation algebraically.

Answer 1

Let the cost of $1$ bat be $Rs.x$ and cost of $1$ ball be $Rs.y$

Case $1:$

$\Rightarrow$ Cost of $6$ balls $6y$

According to the question,

$\Rightarrow$ $3x+6y=3900$

Case $2:$

$\Rightarrow$ Cost of $1$ bat $=x$

$\Rightarrow$ Cost of $3$ balls $3y$

According to the question,

$x+3y=1300$

So, algebraically representation be,

$3x+6y=3900$

$x+3y=1300$