Question

The coach of a cricket team buys one bat and $2$ balls for $Rs.300$. Later he buys another $2$ bats and $3$ balls of the same kind for $Rs.525$. Represent this situation algebraically and solve it by graphical method. Also, find out that how much money the coach will pay for the purchase of one bat and one ball.

Answer 1

Let cost of one bat be $Rs.x$

Let cost of one ball be $Rs.y$

$x+2y=300...........\left(i\right)$ Blue line

$2x+3y=525...........\left(ii\right)$ Red line

The graphs for the equation are shown in the attached plot.

From graph, solution is $x=150,y=75$

Hence, cost of one bat is $Rs.150$ and cost of one ball is $Rs.75$

Cost of one bat and one ball is $Rs.150+Rs.75=Rs.225$