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Standard XII

Chemistry

Gold Number

The coagulati...

Question

The coagulation of $10 {cm}^{3}$ of gold sol by $1 mL$ 10% $N a C l$ solution is completely prevented by addition of $0.025 g$ of starch to it. The gold number of starch is:

25.0

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25.00

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Solution

$0.025 g$ starch add in $10 {cm}^{3}$ gold sol
$∴ 10 {cm}^{3} gold sol contain = 0.025 g$
$1 {cm}^{3} gold sol contain = \frac{0.025 \times 10^{- 3} mg \times 10}{100} = 25$

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The coagulation of 10 cm3 of gold sol by 1 mL 10% NaCl solution is completely prevented by addition of 0.025 g of starch to it. The gold number of starch is:

0.025 g starch add in 10 cm3 gold sol ∴10 cm3gold sol contain=0.025 g 1 cm3gold sol contain=0.025×10−3 mg×10100=25

The coagulation of $10 {cm}^{3}$ of gold sol by $1 mL$ 10% $N a C l$ solution is completely prevented by addition of $0.025 g$ of starch to it. The gold number of starch is:

$0.025 g$ starch add in $10 {cm}^{3}$ gold sol
$∴ 10 {cm}^{3} gold sol contain = 0.025 g$
$1 {cm}^{3} gold sol contain = \frac{0.025 \times 10^{- 3} mg \times 10}{100} = 25$