The coagulation of $200 m l$ of a colloidal solution of gold is completely prevented by adding $0.50 g m$ of starch it before adding $20 m l$ of $10 % N a C l$ solution. Calculate the gold number of starch.

Open in App

Solution

Solution:-
Gold number is the amount of protective colloid in $m g$ that prevents coagulation of $10 m l$ gold sol on addition of $1 m l$ of $10 % N a C l$ solution.
Therefore,
Gold number $= \frac{0.5}{0.2} \times 10 = 25$
Hence the gold no. of starch is $25$ .

Suggest Corrections

Similar questions

Q. The coagulation of 200 ml of a colloidal solution of gold is completely prevented by adding 0.50 g of starch to it before adding 1 ml of 10%

N a C l

solution. Calculate the gold number of starch

Q. The coagulation of 200 ml of a colloidal solution of gold is completely prevented by adding 0.50 g of starch to it before adding 1 ml of 10%

N a C l

solution. Calculate the gold number of starch

Q. The coagulation of

100 m L

of a colloidal solution of gold is completely prevented by adding

0.25 g

of starch to it before adding

10 m L

10

N a C l

solution. Find out the gold number of starch.

Q. The coagulation of

100

mL of a colloidal sol of gold is completely prevented by addition of

0.03

g of haemoglobin to it before adding

1

mL of

10 %

N a C l

solution. Calculate the gold number of haemoglobin.

The coagulation of 100 mL of gold sol is prevented by addition of 0.25 g of starch to it before adding 1 ml of 10% NaCl solution. If the gold number of starch is x then $\frac{x}{5}$ is: ___

Join BYJU'S Learning Program

The coagulation of 200ml of a colloidal solution of gold is completely prevented by adding 0.50 gm of starch it before adding 20ml of 10%NaCl solution. Calculate the gold number of starch.

Solution:-Gold number is the amount of protective colloid in mg that prevents coagulation of 10ml gold sol on addition of 1ml of 10%NaCl solution.Therefore,Gold number =0.50.2×10=25Hence the gold no. of starch is 25.

The coagulation of $200 m l$ of a colloidal solution of gold is completely prevented by adding $0.50 g m$ of starch it before adding $20 m l$ of $10 % N a C l$ solution. Calculate the gold number of starch.

Solution:-
Gold number is the amount of protective colloid in $m g$ that prevents coagulation of $10 m l$ gold sol on addition of $1 m l$ of $10 % N a C l$ solution.
Therefore,
Gold number $= \frac{0.5}{0.2} \times 10 = 25$
Hence the gold no. of starch is $25$ .