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Electrode Potential

The coagulati...

Question

The coagulation value in millimoles per litre of electrolytes used for the coagulation of ${A g}_{2} S_{3}$ are as below:
$I$ . $N a C l = 52$
$I I$ . $K C l = 51$
$I I I$ . $B a {C l}_{2} = 0.69$
$I V$ . $M g {S O}_{4} = 0.22$
The correct order of their flocculating power is:

M g S O_{4} > B a C l_{2} > K C l > N a C l

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M g S O_{4} > K C l > B a C l_{2} > N a C l

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M g S O_{4} > N a C l > B a C l_{2} > K C l

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M g S O_{4} > B a C l_{2} > N a C l > K C l

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Solution

The correct option is A $M g S O_{4} > B a C l_{2} > K C l > N a C l$
The minimum amount of an electrolyte required to cause precipitation of one liter of a colloidal solution is called the coagulation value or flocculation value of the electrolyte for the sol. The reciprocal of coagulation value is regarded as the coagulating power.
The correct order of flocculating power will be $M g S O_{4} > B a C l_{2} > K C l > N a C l$

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Similar questions

A s_{2} S_{3}

(N a C l) = 52

(B a C l_{2}) = 0.69

(M g S O_{4}) = 0.22

A s_{2} S_{3}

N a C l, i t i s 52,

B a C l_{2}, i t i s 0.69,

M g S O_{4}, i t i s 0.22

A s_{2} S_{3}

I . (N a C l) = 52, I I . (B a C l_{2}) = 0.69, I I I . (M g S O_{4}) = 0.22

A s_{2} S_{3}

N a C l, i t i s 52,

B a C l_{2}, i t i s 0.69,

M g S O_{4}, i t i s 0.22

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