The coefficient B in the virial equation of state has unit:

$P V_{m} = R T (1 + \frac{B}{V_{m}} + \frac{C}{V_{m}^{2}} + . . . . .)$

mole

No worries! We‘ve got your back. Try BYJU‘S free classes today!

L/mole

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

L-mole

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C L/mole
Unit of L.H.S = Unit of R.H.S
$P : a t m, V_{m} : L, R : L - a t m m o l e^{- 1} K^{- 1}$
$(L - a t m) = L - a t m m o l e^{- 1} K^{- 1} \times K (1 + B / L + C / L^{2} + . . . . . .)$
$m o l e = (1 + B / L + C / L^{2} + . . . . . .)$
The unit of B is $L - m o l e$ , similarly for C is $L^{2} - m o l e$
Option B is correct.

Suggest Corrections

Similar questions

P V_{M} = R T [A + \frac{B}{V_{M}} + \frac{C}{V_{M}^{2}} + . . .]

A, B, C, . . .

P V_{m} = R T (1 + \frac{B}{V_{m}} + \frac{B}{V_{m}^{2}} + . . .)

V_{m}

P V_{m} = R T (1 + \frac{B}{V_{m}} + \frac{C}{V_{m}^{2}} + . . .)

V_{m}

P V_{m} = R T (1 + \frac{B}{V_{m}} + \frac{C}{V_{m}^{2}} + . . .)

V_{m}

Z vs \frac{1}{V_{m}}

Z = 1 + (b - \frac{a}{R T}) \frac{1}{V_{m}} + \frac{b^{2}}{V_{m}^{2}} + \frac{b^{3}}{V_{m}^{3}} + \dots \dots

(V_{c})

{cm}^{3}

Join BYJU'S Learning Program