The coefficient of absorption of a surface is $0.6$ . When radius heat is incident in the surface at $1500 J / m i n$ , the energy reflected in $5$ minutes is $450 J$ . The coefficient of transmission of the surface is:

0.06

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0.28

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0.34

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0.08

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Solution

The correct option is C $0.34$
CO-efficient of absorption $= a = 0.6$
Co-efficient of transmission $= \frac{E n e r g y t r a n s m i t t e d}{I n c i d e n t E n e r g y} = t$
Co-efficient of reflection $= \frac{E n e r g y r e f l e c t e d}{I n c i d e n t e n e r g y} = \frac{450}{1500 \times 5} = \frac{3}{50} = 0.06$
$\Rightarrow a + t + r = 1 \Rightarrow t = 1 - (a + r) = 1 - (0.6 + 0.6) = 1 - 0.66 = 0.34$

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The coefficient of absorption of a surface is 0.6. When radius heat is incident in the surface at 1500J/min, the energy reflected in 5 minutes is 450J. The coefficient of transmission of the surface is:

The correct option is C 0.34CO-efficient of absorption =a=0.6Co-efficient of transmission =EnergytransmittedIncidentEnergy=tCo-efficient of reflection =EnergyreflectedIncidentenergy=4501500×5=350=0.06⇒a+t+r=1⇒t=1−(a+r)=1−(0.6+0.6)=1−0.66=0.34

The coefficient of absorption of a surface is $0.6$ . When radius heat is incident in the surface at $1500 J / m i n$ , the energy reflected in $5$ minutes is $450 J$ . The coefficient of transmission of the surface is: