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Question

The coefficient of apparent expansion of mercury in a glass vessel is 153×106/C and in a steel vessel is 144×106/C. If α for steel is then, that of glass is 12×106/C.then that of glass is

A
9×106/C.
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B
6×106/C.
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C
36×106/C.
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D
27×106/C.
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Solution

The correct option is D 9×106/C.
Weknowthatγreal=γapparent+γvesselSo,(γapp+γvessel)glass=(γapp+γvessel)steel(γrealissameinbothcases)or153×106+(γvessel)glass=144×106+(γ_{vessel})_{steel}Further(γ_vessel)_{steel}=3α=3×(12×106)=36×106/C153×106+(γvessel)glass=144×106+36×106Solvingweget(γ_{vessel})_{glass}=27×106/C(γ_{vessel})_{glass}orα=γglass3=9×106/C

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