wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

The coefficient of friction between 4kg or 5kg blocks is 0.2 and between 5kg block and ground is 0.1 respectively. Choose the correct statements.(Take g=10m/s2)
135424_53fd0911ef9e4b97b7b016c4a86631a4.png

A
Minimum force needed to cause system to move is 17N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
When force is 4N static friction at all surfaces is 4N to keep system at rest
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Maximum acceleration of 4kg block is 2m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Slipping between 4kg blocks start when F is 17N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Maximum acceleration of 4kg block is 2m/s2
Friction force between 5kg block and ground is f=0.1×(5+4)×10=9N
So, a minimum of 9N force is required to move the system and 4kg block starts when F=9N
From FBD of 4kg block, 4a=f=0.2×4×10=8,a=2m/s2
Thus,maximum acceleration of 4kg block is 2m/s2
150667_135424_ans_2a60d8346f97456f8e0e77d308c96e8f.png

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservative Forces and Potential Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon