The coefficient of friction between 4kg or 5kg blocks is 0.2 and between 5kg block and ground is 0.1 respectively. Choose the correct statements.(Take g=10m/s2)
A
Minimum force needed to cause system to move is 17N
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B
When force is 4N static friction at all surfaces is 4N to keep system at rest
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C
Maximum acceleration of 4kg block is 2m/s2
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D
Slipping between 4kg blocks start when F is 17N
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Solution
The correct option is B Maximum acceleration of 4kg block is 2m/s2 Friction force between 5kg block and ground is f=0.1×(5+4)×10=9N So, a minimum of 9N force is required to move the system and 4kg block starts when F=9N From FBD of 4kg block, 4a=f=0.2×4×10=8,a=2m/s2 Thus,maximum acceleration of 4kg block is 2m/s2