Question

The coefficient of friction between the tyres and the road is $\mu$. A car is moving with momentum $p$. What will be the stopping distance due to friction alone ? The mass of the car is $m$.

• A. $\frac{p^2}{2\mu g}$
• B. $\frac{p^2}{2mg}$
• C. $\frac{p^2}{2m^2\mu g}$
• D. $\frac{p^2}{mg}$

Answer 1

Answer: (C)

$\frac{p^2}{2m^2\mu g}$

$K=p^2/2m=\mu mgx$
Hence, $x=p^2/2m^2\mu g$.