The coefficient of mutual inductance of two circuits A and B is 3mH and their respective resistance is 10 - and 4- How much current should change in 0-02 s in circuit A- so that the induced current in B should be 0-0060 A-

The correct option is B 0.16 A induced current in #160;B=0.006 A=6× 10^ 3A induced emf in #160;B=6× 10^ 3× 4V=24× 10^ 3V Now, #160;MdIdt=24 ...

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Standard XII

Physics

Lenz's Law

The coefficie...

Question

The coefficient of mutual inductance of two circuits A and B is $3 m H$ and their respective resistance is $10 Ω$ and $4 Ω$ . How much current should change in $0.02$ s in circuit A, so that the induced current in B should be $0.0060 A ?$

0.24 A

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1.6 A

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0.18 A

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0.16 A

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Solution

The correct option is B $0.16 A$
induced current in $B = 0.006 A = 6 \times 10^{- 3} A$
induced emf in $B = 6 \times 10^{- 3} \times 4 V = 24 \times 10^{- 3} V$
Now, $M \frac{d I}{d t} = 24 \times 10^{- 3}$
or, $d I = \frac{24 \times 10^{- 3} \times 0.02}{3 \times 10^{- 3}} A = 0.16 A$

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The coefficient of mutual inductance of two circuits A and B is 3mH and their respective resistance is 10Ω and 4Ω. How much current should change in 0.02 s in circuit A, so that the induced current in B should be 0.0060A?

The correct option is B 0.16Ainduced current in B=0.006A=6×10−3Ainduced emf in B=6×10−3×4V=24×10−3VNow, MdIdt=24×10−3or, dI=24×10−3×0.023×10−3A=0.16A

The coefficient of mutual inductance of two circuits A and B is $3 m H$ and their respective resistance is $10 Ω$ and $4 Ω$ . How much current should change in $0.02$ s in circuit A, so that the induced current in B should be $0.0060 A ?$

The correct option is B $0.16 A$
induced current in $B = 0.006 A = 6 \times 10^{- 3} A$
induced emf in $B = 6 \times 10^{- 3} \times 4 V = 24 \times 10^{- 3} V$
Now, $M \frac{d I}{d t} = 24 \times 10^{- 3}$
or, $d I = \frac{24 \times 10^{- 3} \times 0.02}{3 \times 10^{- 3}} A = 0.16 A$