The coefficient of performance of a refrigerator is 5 . If the temperarture inside freezer is −200C, the temperature of the surroundings to which it rejects heat is
A
21°C
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B
31°C
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C
41°C
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D
11°C
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Solution
The correct option is B31°C 5=heatworkdone 5=T(fr)T(surr)−T(fr) 5=253KT−253 5T−1265=253 5T=1518 T=303.6Kor30.60C We get, T=30.60C.