The coefficient of performance of a refrigerator is given by:

\frac{θ_{2}}{θ_{1} - θ_{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{θ_{1}}{θ_{1} - θ_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{θ_{1} - θ_{2}}{θ_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{θ_{1} - θ_{2}}{θ_{1}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{θ_{2}}{θ_{1} - θ_{2}}$
The coefficient of a refrigrator,
$Θ_{2} =$ The heat em over by the coed reservoir
$Θ_{1} =$ The heat sufflied to the hot reservoir
$C . O . P$ cooling $= \frac{Θ_{2}}{Θ_{1} - Θ_{2}}$
The coefficient of performance of a heat pump depends on its dety. The heat rejected to the hot sink is greater than the heat absorbed from the cold source.

Suggest Corrections

Similar questions

Q. If

\frac{{cos}^{4} θ}{θ_{1}} + \frac{{sin}^{4} θ}{θ_{2}} = \frac{1}{θ_{1} + θ_{2}}

,then

\frac{θ_{2} + θ_{1}}{θ_{1}}

equals

Q. If

\frac{{cos}^{4} x}{θ_{1}} + \frac{{sin}^{4} x}{θ_{2}} = \frac{1}{θ_{1} + θ_{2}},

then

\frac{θ_{2}}{θ_{1}}

equals

If $t a n θ_{1}, t a n θ_{2}, t a n θ_{3}$ are the real roots of $x^{3} - (a + 1) x^{2} + (b - a) x - b = 0 w h e r e θ_{1}, θ_{2}, θ_{3}$ are acute then $θ_{1} + θ_{2} + θ_{3} =$

θ_{1} + θ_{2}

is constant

(= 2 a)

cot θ_{1} + cot θ_{2}

is constant

(= d)

Join BYJU'S Learning Program