The coefficient of self induction of two inductor coils are $20 m H$ and $40 m H$ respectively. If the coils are connected in series so as to support each other and the resultant inductance is $80 m H$ then the value of mutual inductance between the coils will be

5 m H

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10 m H

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20 m H

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40 m H

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Solution

The correct option is B $10 m H$
$L_{t o t a l} = L_{1} + L_{2} + 2 M$

$80 m H = 20 m H + 40 m H + 2 M$

$∴ M = 10 m H$

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The coefficient of self induction of two inductor coils are 20mH and 40mH respectively. If the coils are connected in series so as to support each other and the resultant inductance is 80mH then the value of mutual inductance between the coils will be

The correct option is B 10mHLtotal=L1+L2+2M80mH=20mH+40mH+2M∴M=10mH

The coefficient of self induction of two inductor coils are $20 m H$ and $40 m H$ respectively. If the coils are connected in series so as to support each other and the resultant inductance is $80 m H$ then the value of mutual inductance between the coils will be

The correct option is B $10 m H$
$L_{t o t a l} = L_{1} + L_{2} + 2 M$

$80 m H = 20 m H + 40 m H + 2 M$

$∴ M = 10 m H$