The coefficient of static and kinetic friction between the two blocks and also between the lower block and the ground are -s- 0-6 and -k- 0-4- Find the value of tension T applied on the lower block at which the upper block begins to slip relative to lower block-

You visited us 10 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Finding Friction's Magnitude

The coefficie...

Question

The coefficient of static and kinetic friction between the two blocks and also between the lower block and the ground are $μ_{s} = 0.6$ and $μ_{k} = 0.4$ . Find the value of tension $T$ applied on the lower block at which the upper block begins to slip relative to lower block.

20 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

60 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

80 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $40 N$
The maximum static friction on upper and lower block is $f_{1 m a x} = μ_{s} m_{1} g = 0.6 \times 2 \times 10 = 12 N$
The maximum static friction between ground and lower block is $f_{2 m a x} = μ_{s} (m_{1} + m_{2}) g = 0.6 (2 + 2) 10 = 24 N$
We assume that both blocks move together with acceleration a to the right
so, $(m_{1} + m_{2}) a = T - μ_{k} (m_{1} + m_{2}) g$
or $4 a = T - 0.4 (2 + 2) 10$ or $a = \frac{T - 16}{4}$
for upper block, $f_{1} = 2 a = \frac{T - 16}{2}$
For just sliding, $f_{1} = f_{1 m a x}$ or $\frac{T - 16}{2} = 12$
or $T - 16 = 24 \Rightarrow T = 40 N$

Suggest Corrections

Similar questions

Q. A system of two blocks is shown in figure. Friction coefficient between 5 kg and 10 kg block is

μ = 0.6

and between 10 kg and ground is

μ = 0.4

. What will be the maximum value of force

F

, which is applied at the lower block so that 5 kg block does not slip over 10 kg block?

(g = 10 m / s^{2})

The force applied at the upper block is having fixed magnitude of 80 N (both forces start to act simultaneously).

Q. The friction coefficient between the two blocks shown in the figure is

μ

and the horizontal plane is smooth. What can be the maximum amplitude

(A)

if the upper block does not slip relative to the lower block ?

Q. Two identical blocks of weight

W

are placed one on top of the other as shown in the figure. The upper block is tied to the wall. The coefficient of static friciton between

B

and the ground is

μ

and there is no friction between

A

and

B

. When

F = μ W

force is applied on the lower block as shown, the tension in the string will be

A 2 kg block is placced over a 4 kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 0.20. Find the acceleration of the two blocks if a horizontal force of 12 N is applied to (a) the upper block, (b) the lower block. Take $g = 10 m / s^{2}$

Q. A block of mass

m = 1 k g

placed on top of another block of mass

M = 5 k g

is attached to a horizontal spring of force constant

k = 20 N / m

as shown in figure. The coefficient of friction between the blocks is

μ

where as the lower block slides on a frictionless surface. The amplitude oscillation is 0.4 m. What is the minimum value of

μ

such that the upper block does not slip over the lower block?

Join BYJU'S Learning Program

The coefficient of static and kinetic friction between the two blocks and also between the lower block and the ground are μs=0.6 and μk=0.4. Find the value of tension T applied on the lower block at which the upper block begins to slip relative to lower block.

The coefficient of static and kinetic friction between the two blocks and also between the lower block and the ground are $μ_{s} = 0.6$ and $μ_{k} = 0.4$ . Find the value of tension $T$ applied on the lower block at which the upper block begins to slip relative to lower block.