wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The coefficient of static and kinetic friction between the two blocks and also between the lower block and the ground are μs=0.6 and μk=0.4. Find the value of tension T applied on the lower block at which the upper block begins to slip relative to lower block.
135456_9b190bdb0a0b4206a19d8a2db3292082.png

A
20N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
40N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
60N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
80N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 40N
The maximum static friction on upper and lower block is f1max=μsm1g=0.6×2×10=12N
The maximum static friction between ground and lower block is f2max=μs(m1+m2)g=0.6(2+2)10=24N
We assume that both blocks move together with acceleration a to the right
so, (m1+m2)a=Tμk(m1+m2)g
or 4a=T0.4(2+2)10 or a=T164
for upper block, f1=2a=T162
For just sliding, f1=f1max or T162=12
or T16=24T=40N

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon