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Question

# The coefficient of static friction, μs, between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless. (g=10 m/s2)

A
2.0 kg
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B
4.0 kg
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C
0.2 kg
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D
0.4 kg
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Solution

## The correct option is D 0.4 kgFree body diagrams of two masses are We get equations T−f=mAa and f=μN=μmAg ⇒T=mAa+μmAg and T=mBg (for a=0) ∴μN=mBg⇒mB=μmA=0.2×2=0.4 kg. Hence, the correct answer is option (d).

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