wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The coefficient of t32 in the expansion of (1+t2)12(1+t12)(1+t24) is

A
12C10+12C4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
12C5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12C6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12C7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 12C10+12C4
(1+t2)12(1+t12)(1+t24)
=(1+t12)(1+t24)(1+t2)12
=(1+t12+t24+t36)expansion of (1+t2)12
=(1+t12+t24+t36)(1+12C1t2+12C2(t2)2+12C3(t2)3+12C4(t2)4+12C5(t2)5+12C6(t2)6+12C7(t2)7+12C8(t2)8+12C9(t2)9+12C10(t2)10+12C11+12C12(t2)12)
=(1+t12+t24+t36)(1+12C1t2+12C2t4+12C3t6+12C4t8+12C5t10+12C6t10+12C7t14+12C8t16+12C9t18+12C10t20+12C11t22+12C12t24)
Terms containing t32 is
=(t24)12C4t8+(t12)12C10t20
Co-efficients 12C10+12C4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What is Binomial Expansion?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon