The coefficient of the term independent of $x$ in expansion ${(x^{2} - \frac{1}{x})}^{9}$ is :

48

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- 1

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- 24

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84

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Solution

The correct option is D $84$

$T_{r + 1} =^{9} C_{6} (x^{2})^{9 - r} {(\frac{- 1}{x})}^{r}$
Equating the power of $x = 0$
$⟹ 18 - 3 r = 0$
$⟹ r = 6$
Coefficient $=^{9} C_{6} (- 1)^{r} = 84$

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