Question

The coefficient of variation of two series are 58% and 69%. If their standard deviations are 21.2 and 15.6, then their A.Ms are

• A. 36.6,22.6
• B. 34.8, 22.6
• C. 36.6, 24.4
• D. none of these

Answer 1

The correct option is A 36.6,22.6

$\text{We know that}\text{C.V =}\frac{\sigma \times 100}{\overline{x}}or\overline{x}=\frac{\sigma }{c.v}\times 100\therefore \text{Mean of first series =}\frac{21.2\times 100}{58}=\text{36.6}\text{Mean of second series =}\frac{15.6\times 100}{69}=\text{22.6}$