Question

The coefficient of variation of two series are 58% and 69%. If their standard deviations are 21.2 and 15.6, then their A.Ms are

• A. 36.6,22.6
• B. 34.8, 22.6
• C. 36.6, 24.4
• D. none of these

Answer 1

The correct option is A

36.6,22.6

$\text{We know that}C.V=\frac{\sigma \times 100}{\overline{x}}or\overline{x}=\frac{\sigma }{c.v}\times 100\therefore \text{Mean of first series}=\frac{21.2\times 100}{58}=36.6\text{Mean of second series}=\frac{15.6\times 100}{69}=22.6$