The coefficient of volume expansion of a gas is:

\frac{1}{273}

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\frac{2}{273}

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\frac{3}{273}

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\frac{4}{273}

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Solution

The correct option is A $\frac{1}{273}$
According to Charles' law $V_{t} = V_{0} (1 + \frac{t}{273})$
$V_{t} = V_{0} (1 + α t)$ $α = \frac{1}{273} = Coefficent of volume expansion$ Here, $V_{0} = Volume at 0^{\circ} C$ and $V_{t} = Volume at t^{\circ} C$

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Charles' Law

Standard XII Chemistry

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The coefficient of volume expansion of a gas is:

The correct option is A 1273According to Charles' law Vt=V0(1+t273) Vt=V0(1+αt) α=1273=Coefficent of volume expansion Here, V0=Volume at 0 ∘C and Vt=Volume at t ∘C

The correct option is A $\frac{1}{273}$
According to Charles' law $V_{t} = V_{0} (1 + \frac{t}{273})$
$V_{t} = V_{0} (1 + α t)$ $α = \frac{1}{273} = Coefficent of volume expansion$ Here, $V_{0} = Volume at 0^{\circ} C$ and $V_{t} = Volume at t^{\circ} C$