The correct option is A 1.47×10−2
Given:
Coefficient of volume expansion of glycerin, γ=49×10−5 ∘C−1
Change in temperature, ΔT=30∘C
We know that, due to thermal expansion, density as a function of temperature is given by,
ρ=ρ0(1+γΔT)
⇒ρ(1+γΔT)=ρ0
⇒ρ−ρ0=−ργΔT
⇒ρ−ρ0ρ=−γΔT
=−49×10−5×30=−1.47×10−2
The negative sign indicates that the density decreases with increase in temperature.