The coefficient of volume expansion of mercury is 20 times the coefficient of linear expansion of glass. Find the volume of mercury that must be poured into a glass vessel of volume V so that the volume above mercury may remain constant at all temperature

$\frac{V}{10}$

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$\frac{3 V}{10}$

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$\frac{5 V}{10}$

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$\frac{3 V}{20}$

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Solution

The correct option is D
$\frac{3 V}{20}$

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The coefficient of volume expansion of mercury is $20$ times the coefficient of linear expansion of glass. Find the volume of mercury that must be poured into a glass vessel of volume V so that the volume above mercury may remain constant at all temperature

The coefficient of volume expansion of mercury is $20 t i m e s$ the coefficient of linear expansion of glass. If the volume of mercury that must be poured into a glass vessel of volume $V$ so that the volume above mercury may remain constant at all temperature is $\frac{x V}{20} .$ Find $x .$

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Q. The volume of glass vessel is

1000 c c

20^{\circ} C

. What volume of mercury should be poured into it at this temperature so that the volume of the remaining space does not change with temperature? Coefficient of cubical expansion of mercury and glass are

1.8 \times 10^{- 4} /^{\circ} C a n d 9.0 \times 10^{- 5} /^{\circ} C

respectively.

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The coefficient of volume expansion of mercury is 20 times the coefficient of linear expansion of glass. Find the volume of mercury that must be poured into a glass vessel of volume V so that the volume above mercury may remain constant at all temperature

The correct option is D 3V20

The correct option is D
$\frac{3 V}{20}$