The coefficient of volumetric expansion of mercury is $18 \times 10^{- 5} /^{\circ} C$ . A thermometer bulb has a volume $10^{- 6} m^{3}$ and cross section of stem is 0.004 ${c m}^{2}$ Assuming that bulb is filled with mercury at $0^{\circ} C$ then the length of the mercury column at $100^{\circ} C$ is

18.8 mm

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9.2 mm

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7.4 cm

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4.5 cm

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Solution

The correct option is B 4.5 cm
The volume expansion at $100^{\circ} C$ is given as,

$Δ V = V_{0} γ \times Δ T$

$Δ V = 10^{- 6} \times 18 \times 10^{- 5} \times 100$
$Δ V = 18 \times 10^{- 9} m^{3}$
The length of the mercury column is given as, $l = \frac{Δ V}{A}$
$= \frac{18 \times 10^{- 9}}{4 \times 10^{- 7}}$
$= 4.5 \times 10^{- 2} m$
Thus, the length of the mercury column is $4.5 c m$ .

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Q. The coefficient of volumetric expansion of mercury is

18 \times 10^{- 5} /^{o} C

. A thermometer bulb has a volume

10^{- 6} m^{3}

and cross section of stem is

0.004 c m^{2}

Assuming that bulb is filled with mercury at

0^{o} C

then the length of the mercury column at

100^{o} C

is :

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A glass bulb of volume 250cc is filled with mercury at 20 $^{0}$ C and the temperature is raised to $100^{0} C$ . If the coefficient of linear expansion of glass is $9 \times 10^{- 6 / 0} C$ Coefficient of absolute expansion of mercury is $18 \times 10^{- 4 / 0} C$ . The volume of mercury that overflows is

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The coefficient of volumetric expansion of mercury is 18×10−5/∘C. A thermometer bulb has a volume 10−6m3 and cross section of stem is 0.004cm2 Assuming that bulb is filled with mercury at 0∘C then the length of the mercury column at 100∘C is

The correct option is B 4.5 cmThe volume expansion at 100∘C is given as,ΔV=V0γ×ΔTΔV=10−6×18×10−5×100ΔV=18×10−9m3The length of the mercury column is given as, l=ΔVA=18×10−94×10−7=4.5×10−2mThus, the length of the mercury column is 4.5cm.