The coefficient of volumetric expansion of mercury is $18 \times 10^{- 5} /^{o} C$ . A thermometer bulb has a volume $10^{- 6} m^{3}$ and cross section of stem is $0.004 c m^{2}$ Assuming that bulb is filled with mercury at $0^{o} C$ then the length of the mercury column at $100^{o} C$ is :

18.8 m m

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9.2 m m

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7.4 c m

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4.5 c m

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Solution

The correct option is A $4.5 c m$
The volume expansion at $100^{\circ} C$ is given as,

$Δ V = V_{0} γ \times Δ T$

$= 10^{- 6} \times 18 \times 10^{- 5} \times 100$

$= 18 \times 10^{- 9} m^{3}$

The length of the mercury column is given as,

$l = \frac{Δ V}{A}$

$= \frac{18 \times 10^{- 9}}{4 \times 10^{- 7}}$

$= 4.5 \times 10^{- 2} m$

Thus, the length of the mercury column is $4.5 c m$ .

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The coefficient of volumetric expansion of mercury is $18 \times 10^{- 5} /^{o} C$ . A thermometer bulb has a volume $10^{- 6} m^{3}$ and cross section of stem is $0.004 c m^{2}$ . Assuming that bulb is filled with mercury at 0ºC then the length of the mercury column at 100ºC is

The coefficient of volumetric expansion of mercury is $8 \times 10^{- 5}^{\circ} C$ . A thermometer bulb has a volume $10^{- 6} m^{3}$ and cross section of stem is $0.004 c m^{2}$ . Assuming that bulb is filled with mercury at $0^{\circ} C$ , then the length of the mercury column at $100^{\circ} C$ is:

Q. The coefficient of volumetric expansion of mercury is

18 \times 10^{- 5} /^{\circ} C

. A thermometer bulb has a volume

10^{- 6} m^{3}

and cross section of stem is 0.004

{c m}^{2}

Assuming that bulb is filled with mercury at

0^{\circ} C

then the length of the mercury column at

100^{\circ} C

Q. A glass bulb of volume

250 c c

is filled with mercury at

20^{o} C

and the temperature is raised to

100^{o} C

. If the coefficient of linear expansion of glass is

9 \times 10^{- 6} /^{o} C

. Coefficient of absolute expansion of mercury is

18 \times 10^{- 5} /^{o} C

. The volume of mercury overflows

The coefficient of linear expansion of glass is $α_{g}$ per $^{0} C$ and the cubical expansion of mercury is $γ_{m} p e r^{o} C$ . The volume of the bulb of a mercury thermometer at $0^{o} C$ is $V_{0}$ and cross- section of the capillary at $T^{o} C$ is $A_{0}$ , if the mercury just fills the bulb at $0^{0} C$ , height of the column is

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The coefficient of volumetric expansion of mercury is 18×10−5/oC. A thermometer bulb has a volume 10−6m3 and cross section of stem is 0.004cm2 Assuming that bulb is filled with mercury at 0oC then the length of the mercury column at 100oC is :

The correct option is A 4.5cmThe volume expansion at 100∘C is given as, ΔV=V0γ×ΔT =10−6×18×10−5×100 =18×10−9m3 The length of the mercury column is given as, l=ΔVA =18×10−94×10−7 =4.5×10−2m Thus, the length of the mercury column is 4.5cm.

The coefficient of volumetric expansion of mercury is $18 \times 10^{- 5} /^{o} C$ . A thermometer bulb has a volume $10^{- 6} m^{3}$ and cross section of stem is $0.004 c m^{2}$ Assuming that bulb is filled with mercury at $0^{o} C$ then the length of the mercury column at $100^{o} C$ is :