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Question

The coefficient ofx103 in (1+x+x2+x3+x4)199.(x1)201 is


A

8

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B

9

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C

0

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D

11

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Solution

The correct option is C

0


[(x1)(x4+x3+x2+x+1)]199(x1)2

=(x51)199(x22x+1)

Coefficient of x103 is 0 [(x51)199 will have all powers of x as multiples of 5 only ]


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