The coefficient of x2 in the expansion of the product (2–x2)[(1+2x+3x2)6+(1–4x2)6] is
A
107
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B
108
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C
155
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D
106
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Solution
The correct option is D106 (2–x2)[(1+2x+3x2)6+(1–4x2)6]=2[(1+2x+3x2)6+(1–4x2)6]−x2[(1+2x+3x2)6+(1–4x2)6]⇒coefficient ofx2=2⋅coefficient ofx2in[(1+2x+3x2)6+(1–4x2)6]−constant term in[(1+2x+3x2)6+(1–4x2)6](1+2x+3x2)6=6∑r=06Cr(2x+3x2)r=6C0+6C1(2x+3x2)+6C2(2x+3x2)2+.....⇒coefficient ofx2=2(18+60−24)−2=106