The coefficient of x24 in 1 - 3x - 6x2 - 10x3 - -2-3

The correct option is C 125 S = 1 + 3x = 6x^2 + 10x^3 + .... ∞ 7r + 1 = 1, 3, 6, 10 ⇒ nbsp; (r^2 + r2) . x^r ⇒ x^24→ 5^3 coefficient ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Ratio and Proportion

The coefficie...

Question

The coefficient of $x^{24}$ in ${(1 + 3 x + 6 x^{2} + 10 x^{3} + . . . . . . . . \infty)}^{2 / 3}$

25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

125

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

50

No worries! We‘ve got your back. Try BYJU‘S free classes today!

300

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

x^{24}

(1 + 3 x + 6 x^{2} + 10 x^{3} + - - - - + \infty)^{2 / 3} =

x^{n}

(1 - 3 x + 6 x^{2} - 10 x^{3} + . . . + (- 1)^{r} \frac{(r + 1) (r + 2) x^{r}}{2} + . . . \infty)^{- n}

The coefficient of $x^{r}$ in the expansion of (1+3x+6 $x^{2} + 10 x^{3}$ +......) is :

{(1 + 2 x + 3 x^{2} + 4 x^{3} + \dots \dots . \infty)}^{3 / 2} = 1 + 3 x + 6 x^{2} + 10 x^{3} + \dots \dots, \infty,

| x | < 1

1 + 3 x + 6 x^{2} + 10 x^{3} + . . . .

Join BYJU'S Learning Program