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Question

The coefficient of x256 in the expansion of (1x)101(x2+x+1)100 is

A
100C15
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B
100C16
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C
100C16
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D
100C15
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Solution

The correct option is A 100C15
(1x)101(x2+x+1)100
(1x)((1x)(1+x+x2))100
(1x)(1x3)100
General term in (1x3)100 is 100Cr(x3)r= 100Cr(x)3r

x256 occurs if 3r=256 or 3r+1=256

r=2563 (not valid) r=2553=85

Coefficient of x256 is (1)100C85= 100C15

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