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Question

The coefficient of x3 in the expansion of (xmx)11 is


A

924m7

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B

792m5

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C

792m6

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D

330m7

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Solution

The correct option is C

792m6


Let x3 occur at (r+1)th term in the given expansion.

Then, we have:

Tr+1=11Crx11r(mx)r

=(1)r×11Crmrx11rr

For this term to contain x3, we must have:

11-2r =-3

r=7

Required coefficient

=(1)711C7m7

=11×10×9×84×3×2m7

=330m7


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