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Question

The coefficient of x4 in the expansion of (1+x+x2+x3)6 in powers of x, is

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Solution

(1+x+x2+x3)6
=[(1+x)+x2(1+x)]6
=(1+x)6(1+x2)6
Coefficient of x4
=6C0×6C2+6C2×6C1+6C4×6C0
=1×15+15×6+15×1=15+90+15=120
Coefficient of x4=120

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