CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The coefficient of x4 in the expansion of (1+x+x2+x3)6 in powers of x, is

Open in App
Solution

(1+x+x2+x3)6
=[(1+x)+x2(1+x)]6
=(1+x)6(1+x2)6
Coefficient of x4
=6C0×6C2+6C2×6C1+6C4×6C0
=1×15+15×6+15×1=15+90+15=120
Coefficient of x4=120

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Binomial Theorem for Any Index
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon