The correct option is C 705
(1+x+x2+x3)10=[(1+x)+x2(1+x)]10=(1+x)10(1+x2)10=∑ 10Cr1xr1 10Cr2x2r2=∑ 10Cr1 10Cr2 xr1+2r2
For the coefficient of x4, r1+2r2=4
There will be three cases:
(i) r1=4, r2=0, (ii) r1=2, r2=1, (iii) r1=0, r2=2,
The coefficient of x4 in the expansion is 10C4 × 10C0+ 10C2× 10 C1+10C0 × 10C2=705